[frookenhauer]

Nice one AIJ...An interim one while we bash our heads figuring out the hard one

Unfortunately I'm not getting it either

[Stradivarius]

a secret?

[Mentalist]

Ain't_It_Just_, on Feb 28 2009, 01:04 AM, said:

Here's a tricky one (I hope)

What is too much for one, enough for two, and nothing to three?

i'll take a wild stab and say "love"

[Grimjust Bearegular]

"O"..as in the letter?

[frookenhauer]

probably...AIJ is that correct?!

[Mavnak]

For the seven men one:
i'd ask them if they're the man im looking for then smack the group of four around until he gave in.

PS: they're not very well trapped are they.

This post has been edited by Mavnak: 03 March 2009 - 06:21 AM

[Impirion]

I vote STD is not allowed to post any more riddles, they hurt the mind

[Sir Thursday]

This one really isn't that difficult...you've got lots of questions to ask, which simplifies matters.


Sir Thursday

[frookenhauer]

I vote Impirion is right. Damn you STD, you keep forgetting that most of us mere mortals have brains that have been turned to mush though excessive drinking and the imbibing of non/ medicinal drugs for a significant portion of our lives...BTW I never inhaled.

I've tried to wrap my head round it, but it hurts so I'm going to have a crack at it tomorrow...

[Lisheo]

Sir Thursday, on Feb 28 2009, 12:38 AM, said:

Trapped in a room
Are 7 men
Holding 7 keys
To Seven doors
3 tell lies
3 tell truth
The one that you want tells both.
Seven questions you can spare.
To find out who he is and where.

What are your questions? Note that you can't direct a single question at everybody (that would be cheating), and that each man holds the key to the door he is standing next to.

Sir Thursday

Oh, lord, I remember one like this... Give me a while.

[frookenhauer]

Hurrah for Lisheo, lets hope is addiction to booze doesn't hold up the proceedings too long!

[Obdigore]

Sir Thursday, on Feb 27 2009, 06:38 PM, said:

Trapped in a room
Are 7 men
Holding 7 keys
To Seven doors
3 tell lies
3 tell truth
The one that you want tells both.
Seven questions you can spare.
To find out who he is and where.

What are your questions? Note that you can't direct a single question at everybody (that would be cheating), and that each man holds the key to the door he is standing next to.

Sir Thursday

You ask each man to point to all the other men in the room who are able to tell either only the truth or only a lie, but not both.

Someone will be pointed at by 3 men(liars) while they don't point at anyone else, and not pointed at by 3 others(truth), while all others are pointed at.

This post has been edited by Humperdinck: 06 March 2009 - 06:33 PM

[Macros]

Assuming each one will answer a question if he can:
Ask each one "Are the statements 'You always tell the truth.' and 'You will answer this question "No.".' both true or both false?"

The liars and truth-tellers will be unable to answer. The one who does answer has the right key.

eta - damnit humperdinck!

This post has been edited by Macros: 06 March 2009 - 10:55 PM

[Sir Thursday]

Humperdinck, on Mar 6 2009, 06:32 PM, said:

You ask each man to point to all the other men in the room who are able to tell either only the truth or only a lie, but not both.

Someone will be pointed at by 3 men(liars) while they don't point at anyone else, and not pointed at by 3 others(truth), while all others are pointed at.

Yeah, I guess that works, although it kind of stretches the seven questions somewhat. Here is the method I was thinking of:

1) Ask the first three people to give you the answer to a question you know the answer to (for example "What's 2+2?"). You will either get two true or two false answers.

2) If you get two true answers, then you can be sure that one of the two is a truthteller, even if the other one is the one who can do both. So you ask the two people who gave you true answers "Who is the man who can tell both truth and lies?" If they both give the same answer, then that's the guy you're looking for. If they give different answers, then one of the two must be the one you're looking for. In that case, you ask the known liar which one of the two is the one you are looking for, and the one you want is the other one.

3) If you get two liars and one truthteller, then you ask both liars to tell you which of the men you haven't questioned yet can only tell a lie. They will therefore identify for you at least one person who can tell the truth. Now you have two people who can tell the truth you can follow the process outlined in Step 2 to determine who the man you want is.


Sir Thursday

[frookenhauer]

Its so simple when you point out how to do it. I also like the way you introduced diplomacy and tact with regards to the last answer. You're a good man charlie brown.

Right its Maccy who's up for riddling us quick.

[Macros]

old silly riddle is old
but macros is hungover

you're in a room, there's a table and a saw, how do you get out?

[Cause]

cut the table in half. than put the two pieces toghether to make a whole/hole and step through. Works better when you talk. DOes not translate well to talking

[Macros]

no

you walk out the door.

fucking weirdo

[Impirion]

That's brilliant!

Oh and STD, I think I can do your puzzle in 6 questions, so there

This post has been edited by Impirion: 08 March 2009 - 04:51 PM

[Sir Thursday]

Impirion, on Mar 8 2009, 04:50 PM, said:

Oh and STD, I think I can do your puzzle in 6 questions, so there

Oh, I don't doubt you can do it in less. There are tons of different methods to do it in 6. You can just modify my solution so that when you get two liars you ask "Who am I not looking for?", for example. But I don't like asking that question, so I figured I'd post a solution without it .


Sir Thursday